₹ 6,100 was partly invested in Scheme A at 10 | vedclass

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Question

(c) Let amount invested in scheme $A=₹ x$

Let amount invested in scheme $B =₹(6100-x)$

$P_{1}\left[\left(1+\frac{R_{1}}{100}\right)^{T_{1}}-1\ri

Vedclass · Accepted Answer

$4000$

Vedclass · Answer

(c) Let amount invested in scheme $A=₹ x$

Let amount invested in scheme $B =₹(6100-x)$

$P_{1}\left[\left(1+\frac{R_{1}}{100}ight)^{T_{1}}-1ight]=\frac{P_{2} R_{2} T_{2}}{100}$

$x=\left[\left(1+\frac{10}{100}ight)^{2}-1ight]$

$x=\frac{(6100-x) 	imes 10 	imes 4}{100}$

$\Rightarrow x 	imes\left[\left(\frac{11}{10}ight)^{2}-1ight]=4\left(\frac{6100-x}{10}ight)$

$x 	imes\left(\frac{121-100}{100}ight)=\frac{4(6100-x)}{10}$

$\Rightarrow \frac{21 x}{100}=\frac{24400-4 x}{10}$

$21 x=244000-40 x$

$21 x+40 x=244000$

$61 x=244000$

$x=₹ 4000$

₹ $6,100$ was partly invested in Scheme $A$ at $10 \%$ p.a. compound interest (compounded annually) for $2$ years and partly in Scheme $B$ at $10 \%$ p.a. simple interest for $4$ years. Both the schemes pay equal interests. How much was invested (In ₹) in Scheme $A$?

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