“Electric field inside hollow region of conductor in uniform electric field is same”. Explain.
Consider a conductor with a cavity as shown in figure.
There is no charges inside the cavity.
Whatever be the size and shape of the cavity.
If a conductor with cavity placed in external electric field, its electric field in cavity remain zero.
If the conductor is charged or charges are induced on a neutral conductor by an external field, all charges reside only on the outer surface of a conductor with cavity.
Any cavity in a conductor remains shielded from outside electric influence. This is known as electrostatic shielding.
When we are in the car and there is thunder with lighting in the sky, we should closed all doors of the car. If lighting strikes the car, (or live current wire falls on car) electrostatic shielding develops on the outer surface of the car and we are safe inside the car.
The magnitude of electric field on the surface of a uniformly charged metalic spherical shell is $E$. If a hole is made in it using a insulating device, then the magnitude of electric field in the hole will be
Figure shows three concentric metallic spherical shells. The outermost shell has charge $q_2$, the inner most shell has charge $q_1$, and the middle shell is uncharged. The charge appearing on the inner surface of outermost shell is
Consider the shown system of two concentric thin metal shells. The inner hell has charge $Q$, while the outer shell is neutral. Potential difference between the shells is $V$. If the shell are joined by metal wire, then potential of the inner shell is
Assertion : In a cavity within a conductor, the electric field is zero.
Reason : Charges in a conductor reside only at its surface
If $q$ is the charge per unit area on the surface of a conductor, then the electric field intensity at a point on the surface is