Match List-I with List-II. Choose the correct | vedclass

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Question

(A) $A \rightarrow$ Kolbe-Schmidt reaction: Phenol reacts with $NaOH$ followed by $CO_2$ and $HCl$ to form salicylic acid. Matches with $IV$.$B \right

Vedclass · Accepted Answer

$A-IV, B-III, C-I, D-II$

Vedclass · Answer

(A) $A \rightarrow$ Kolbe-Schmidt reaction: Phenol reacts with $NaOH$ followed by $CO_2$ and $HCl$ to form salicylic acid. Matches with $IV$.$B \rightarrow$ Reimer-Tiemann reaction: Phenol reacts with $CHCl_3$ and $NaOH$ followed by $HCl$ to form salicylaldehyde. Matches with $III$.$C \rightarrow$ Oxidation of phenol: Phenol is oxidized by $Na_2Cr_2O_7$ and $H_2SO_4$ to $p$-benzoquinone. Matches with $I$.$D \rightarrow$ Williamson ether synthesis: Phenol reacts with $NaOH$ to form sodium phenoxide,which then reacts with $CH_3Cl$ to form anisole $(PhOCH_3)$. Matches with $II$.Therefore,the correct matching is $A-IV, B-III, C-I, D-II$.

Column-$I$ (Reaction)	Column-$II$ (Product and Reaction Name)
$A$. Phenol $+$ dilute $HNO_3$	$i$. Mononitrophenol,Nitration
$B$. Phenol $+$ Bromine water	$ii$. $2,4,6$-Tribromophenol,Bromination
$C$. Phenol $+$ $Na_2Cr_2O_7/H_2SO_4$	$iii$. Benzoquinone,Oxidation
$D$. Sodium phenoxide $+$ $CO_2$ followed by $H^+$	$iv$. Salicylic acid,Kolbe reaction

Column $(I)$	Column $(II)$	Column $(III)$
$(A)$ Methyl isopropyl ether	$(1)$ ${C_6}{H_5}O{(CH_2)_6}CH_3$	$(i)$ $2$-Methoxypropane
$(B)$ Phenyl isopentyl ether	$(2)$ $CH_3-O-CH(CH_3)_2$	$(ii)$ Methoxyethane
$(C)$ Heptyl phenyl ether	$(3)$ ${C_6}{H_5}-O-CH_2CH_2CH(CH_3)_2$	$(iii)$ $1$-Phenoxyheptane
$(D)$ Ethyl methyl ether	$(4)$ $CH_3CH_2-O-CH_3$	$(iv)$ $1$-Methoxy$-3-$methylbutane (or $3$-Methylbutoxybenzene)

Match List-$I$ with List-$II$. Choose the correct answer from the options given below:

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