Column I
Column II

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(C) . Kohlrausch law is used to calculate the molar conductivity at infinite dilution $(\Lambda_m^o)$ for weak electrolytes,such as $Ca_3(PO_4)_2$. Th

Vedclass · Accepted Answer

$(A-R), (B-S), (C-Q), (D-P)$

Vedclass · Answer

(C) . Kohlrausch law is used to calculate the molar conductivity at infinite dilution $(\Lambda_m^o)$ for weak electrolytes,such as $Ca_3(PO_4)_2$. Thus,$(A-R)$.
$(B)$. Molar conductance $(\Lambda_m)$ is defined by the formula $\Lambda_m = \frac{\kappa 	imes 1000}{M}$. Thus,$(B-S)$.
$(C)$. Specific conductance $(\kappa)$ is defined as $\kappa = \frac{1}{R} 	imes \frac{l}{A}$. Thus,$(C-Q)$.
$(D)$. The degree of ionization $(\alpha)$ of a weak electrolyte is given by the ratio of molar conductivity at a concentration $c$ to the molar conductivity at infinite dilution: $\alpha = \frac{\Lambda_m^c}{\Lambda_m^o}$. Thus,$(D-P)$.
Therefore,the correct sequence is $(A-R), (B-S), (C-Q), (D-P)$.

Column $I$	Column $II$
$(A)$. Kohlrausch law can calculate	$(P)$. $\frac{\Lambda_m^c}{\Lambda_m^o}$
$(B)$. Molar conductance $\Lambda_m$	$(Q)$. $\frac{1}{R} \times \frac{l}{A}$
$(C)$. Specific conductance $\kappa$	$(R)$. $\Lambda_m^o$ of $Ca_3(PO_4)_2$
$(D)$. Degree of ionization of weak electrolyte	$(S)$. $\frac{\kappa \times 1000}{M}$

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