$(CH_3)_3CBr + KOH (aq.) \to (CH_3)_3COH + KBr$. The above reaction is:

An alkyl bromide $(A)$ forms a Grignard reagent which on treatment with water yields $n$-hexane. When $(A)$ is treated with sodium in dry ether,$4,5$-diethyloctane is formed. The structure of $(A)$ is:

The major product obtained in the following reaction is $C_2H_5ONa + (CH_3)_3C-Cl \rightarrow$

Alkyl halides react with $Mg$ in dry ether to form

An alkyl halide $C_3H_7Cl$,on reaction with a reagent $X$ gave the major product $Y$ $(C_4H_7N)$. $Y$ on hydrolysis released a gas,which turns red litmus to blue. What are $X$ and $Y$?

Chloroform is slowly oxidized by air in the presence of light to form: