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(B) Back bonding occurs when a lone pair from one atom is donated into a vacant orbital of an adjacent atom. This often leads to a change in the hybri

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$(i), (iii)$

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(B) Back bonding occurs when a lone pair from one atom is donated into a vacant orbital of an adjacent atom. This often leads to a change in the hybridisation of the central atom to maximize stability.$(i)$ $CCl_3^-$: The carbon atom has a lone pair,but chlorine does not have a vacant orbital available for back bonding. Thus,hybridisation remains $sp^3$.$(ii)$ $CCl_2$: This is a carbene where carbon has a lone pair and a vacant $p$-orbital. Back bonding from $Cl$ to $C$ occurs,but the hybridisation of $C$ remains $sp^2$.$(iii)$ $(SiH_3)_2O$: Oxygen has lone pairs and silicon has vacant $d$-orbitals. Back bonding occurs,changing the geometry,but the hybridisation of $O$ is often considered $sp^3$ in the context of bond angle changes.$(iv)$ $N(SiH_3)_3$: Nitrogen has a lone pair and silicon has vacant $d$-orbitals. Back bonding occurs,changing the hybridisation of $N$ from $sp^3$ to $sp^2$.Therefore,for $(i)$ and $(iii)$,the hybridisation does not change significantly or is not driven by the back bonding mechanism in the same way as $(iv)$.

	Molecule	Hybridization	Geometry	Number of lone pairs of electrons on central atom
$I$	$SiH_4$	$sp^3$	tetrahedral	$0$
$II$	$BeCl_2$	$sp^2$	linear	$1$
$III$	$SF_4$	$dsp^3$	square planar	$1$
$IV$	$SnCl_2$	$sp$	linear	$0$

"Hybridisation of central atom does not always change due to back bonding". This statement is valid for which of the following compounds?
$(i)$ $CCl_3^-$ $(ii)$ $CCl_2$ $(iii)$ $(SiH_3)_2O$ $(iv)$ $N(SiH_3)_3$

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"Hybridisation of central atom does not always change due to back bonding". This statement is valid for which of the following compounds?$(i)$ $CCl_3^-$ $(ii)$ $CCl_2$ $(iii)$ $(SiH_3)_2O$ $(iv)$ $N(SiH_3)_3$